Home
Class 11
CHEMISTRY
[" 19.The number of atoms in "100g" of a...

[" 19.The number of atoms in "100g" of a foc crystal "],[" density "=10.0g/cm^(3)" and cell edge egual to "20" ."],[" is equal to ":18^(2)" and "10=(12times10^(-8))/((2times10^(-8))^(3)times1100)],[[" (a) "5times10^(24)," (b) "5times10^(25)],[" (c) "6times10^(23)," (d) "2times10^(25)]]

Promotional Banner

Similar Questions

Explore conceptually related problems

The number of atoms in 100 g of a fcc crystal with density d= 10 g/ cm^(-3) and cell edge equal to 200 pm, is equal to ____.

The number of atoms in 100 g of an fcc crystal with density = 10.0g cm^(-3) and cell edge equal to 200 pm is equal to

The number of atoms in 100 g of an fcc crystal with density = 10.0g cm^(-3) and cell edge equal to 200 pm is equal to

The number of atoms in 100 g of an fcc crystal with density = 10.0g cm^(-3) and cell edge equal to 200 pm is equal to

The number of atoms is 100 g of a fcc crystal with density = 10.0 g//cm^(3) and cell edge equal to 200 pm is equal to

The number of atoms in 100 g of an FCC crystal with density d = 10 g//cm^(3) and cell edge equal to 100 pm, is equal to