For certain curve `y=f(x)` satisfying `(d^(2)y)/(dx^(2))=6x-4, f(x)` has local minimum value 5 when `x=1`
Global maximum value of `y=f(x)` for `x in [0,2]` is

For a certain curve y=f(x) satisfying (d^(2)y)/(dx^(2))=6x-4,f(x) has a local minimum value 5 when x=1 . The global maximum value of f(x) if 0lexle2 , is

For certain curves y= f(x) satisfying [d^2y]/[dx^2]= 6x-4, f(x) has local minimum value 5 when x=1. 9. Number of critical point for y=f(x) for x € [0,2] (a) 0 (b)1. c).2 d) 3 10. Global minimum value y = f(x) for x € [0,2] is (a)5 (b)7 (c)8 d) 9 11 Global maximum value of y = f(x) for x € [0,2] is (a) 5 (b) 7 (c) 8 (d) 9

For certain curves y= f(x) satisfying [d^2y]/[dx^2]= 6x-4 , f(x) has local minimum value 5 when x=1. 9. Number of critical point for y=f(x) for x € [0,2] (a) 0 (b)1. c).2 d) 3 10. Global minimum value y = f(x) for x € [0,2] is (a)5 (b)7 (c)8 d) 9 11 Global maximum value of y = f(x) for x € [0,2] is (a) 5 (b) 7 (c) 8 (d) 9

For certain curves y= f(x) satisfying [d^2y]/[dx^2]= 6x-4 , f(x) has local minimum value 5 when x=1. 9. Number of critical point for y=f(x) for x € [0,2] (a) 0 (b)1. c).2 d) 3 10. Global minimum value y = f(x) for x € [0,2] is (a)5 (b)7 (c)8 d) 9 11 Global maximum value of y = f(x) for x € [0,2] is (a) 5 (b) 7 (c) 8 (d) 9

For certain curves y= f(x) satisfying [d^2y]/[dx^2]= 6x-4 , f(x) has local minimum value 5 when x=1. find Number of critical point for y=f(x) for x € [0,2] (a) 0 (b)1. c).2 d) 3

For a certain curve y=f(x) satisfying (d^(2)y)/(dx^(2))=6x-4, f(x) has a local minimum value 5 when x=1, Find the equation of the curve and also the gobal maximum and global minimum values of f(x) given that 0lexle2.

For a certain curve y=f(x) satisfying (d^(2)y)/(dx^(2))=6x-4, f(x) has a local minimum value 5 when x=1, Find the equation of the curve and also the gobal maximum and global minimum values of f(x) given that 0lexle2.

The curve y =f (x) satisfies (d^(2) y)/(dx ^(2))=6x-4 and f (x) has a local minimum vlaue 5 when x=1. Then f^(prime)(0) is equal to :

The curve y =f (x) satisfies (d^(2) y)/(dx ^(2))=6x-4 and f (x) has a local minimum vlaue 5 when x=1. Then f^(prime)(0) is equal to :