`(17-2k)/(k-5)=-3`

Show the following equations and check the result. 3(2k+1)-2(k-5)-5(5-2k)=16

Find the value k if the following equations are consistent (k-2)x+(k-1)y=17,(k-1)x+(k-2)y=18 and x+y=5

tan {2tan ^(-1)""((1)/(5))-(pi)/(4)} is equal to - (k )/(17) then find the value of K .

For a reaction, if effective rate constant k' is given b k=(2k_2)/k_3(k_1/k_5)^(1//5) where k_1,k_2,k_3,k_5 are rate constants for different steps of the reaction The effective activation energy is

For a reaction, if effective rate constant k' is given b k=(2k_2)/k_3(k_1/k_5)^(1//5) where k_1,k_2,k_3,k_5 are rate constants for different steps of the reaction Which one is correct ?

For a reaction, if effective rate constant k' is given b k=(2k_2)/k_3(k_1/k_5)^(1//5) where k_1,k_2,k_3,k_5 are rate constants for different steps of the reaction The effective frequency factor

At 298 K, the K_(sp) of Hg_(2)Cl_(2) is 3.2 times 10^(-17)mol^(3)L^(-3) . What is the solubility of Hg_(2)Cl_(2) in water at 298 K?

For what value of k the following distribution is a probability distribution? X=x_(i):0123P(X=x_(i)):2k^(4)3k^(2)-5k^(3)2k-3k^(2)3k-1