The side of triangle ABC is a line parallel to BC. If BE || AC and CFIARS Meet at E and F respectively. So show that: ar (ABF) -ar (ACF)

XY is a line parallel to side BC of a triangle ABC. If BE||AC and CF ||AB meet XY at E and F respectively , show that ar(ABE)=ar(ACF)

XY is a line parallel to side BC of a triangle ABC. If BF ||AC and CF || AB meet XY at E and F respectively, show that ar (ABE) = ar (ACF)

XY is a line parallel to side BC of triangle ABC. If BE II AC and CF II AB meet XY at E and F respectively,show that ar (ABE) = ar (ACF).

XY is a line parallel to side BC of a triangle ABC . If B E ||A C and C F\ ||\ A B meet XY at E and F respectively, show that a r\ (A B E)\ =\ a r\ (A C F)

XY is a line parallel to side BC of a triangle ABC. If B E" "||" "A C and C F" "||" "A B meet XY at E and F respectively, show that a r" "(A B E)" "=" "a r" "(A C F)

In the figure, XY is a line parallel to BC is drawn through A. If BE || CA and CF || BA are drawn to meet XY at E and F respectively. Show that ar(DeltaABE) = ar (DeltaACF).

In the figure, XY is a line parallel to BC is drawn through A. If BE || CA and CF || BA are drawn to meet XY at E and F respectively. Show that ar(DeltaABE) = ar (DeltaACF).

In the figure, XY is a line parallel to BC is drawn through A. If BE || CA and CF || BA are drawn to meet XY at E and F respectively. Show that ar(DeltaABE) = ar (DeltaACF).

ABC is a triangle A line is drawn parallel to BC to meet AB and AC in D and E respectively. Prove that the median through A bisects DE.

In the following figure, F and E are points on the side AD of the triangle ABD. Through F a line is drawn parallel to AB to meet BD at point C . Prove that : ar (Delta ACE ) = ar (quad . BCEF )