Home
Class 12
CHEMISTRY
[" H,Cland o.Combustion of "29.72mg" of ...

[" H,Cland o.Combustion of "29.72mg" of Dieldrin garfs.Man "],[" naseparate analysis "25.31mg" of Dieldrin was converte "],[" pirical formula of Dieldrin? "],[[" (c) "C_(12)H_(8)C_(6)O," (d) "C_(6)H_(4)Cl_(3)O_(2)," 36.",1.44]]

Promotional Banner

Similar Questions

Explore conceptually related problems

Deildrin, an insecticide, contains C,H,Cl and O. Combustion of 29.72 mg of dieldrin gave 41.21 mg CO_2 and 5.63 mg of H_2O . In a separate analysis 25.31mg of dieldrin was converted into 57.13 mg Ag Cl. What is the empirical formula of dieldrin ?

Deildrin, an insecticide, contains C,H,Cl and O. Combustion of 29.72 mg of dieldrin gave 41.21 mg CO_2 and 5.63 mg of H_2O . In a separate analysis 25.31mg of dieldein was converted into 57.13 mg Ag Cl. What is the empirical formula of diedrin ?

Deildrin, an insecticide, contains C,H,Cl and O. Combustion of 29.72 mg of dieldrin gave 41.21 mg CO_2 and 5.63 mg of H_2O . In a separate analysis 25.31mg of dieldein was converted into 57.13 mg Ag Cl. What is the empirical formula of diedrin ?

Deildrin, an insecticide, contains C,H,Cl and O. Combustion of 29.72 mg of dieldrin gave 41.21 mg CO_2 and 5.63 mg of H_2O . In a separate analysis 25.31mg of dieldein was converted into 57.13 mg Ag Cl. What is the empirical formula of diedrin ?

An inorganic compound on analysis was found to have following composition : Mg = 9.76%, S = 13.01%, O = 26.01%, H_2O = 51.22% Calculate the empirical formula of the compound.

Estimation of phosphorous: Second method: A known mass of compound is heated with fuming HNO_(3) or sodium peroxide (Na_(2)O_(2) in Carius tube which converts phosphorous to H_(3)PO_(4) . Magnesia mixture (MgCl_(2)+NH_(4)Cl) is then added, which gives the percipate of magnesium ammonium phosphate (MgNH_(4).PO_(4)) which on heating gives magnesium pyrophosphate (Mg_(2)P_(2)O_(7)) , which is weighted. Percentage of P =("Atomic mass of P")/("Molecular mass of " Mg_(2)P_(2)O_(7)) xx ("Molecular mass of "Mg_(2)P_(2)O_(7) xx 100)/("Mass of compound")=(62)/(222) xx("Mass of " Mg_(2)P_(2)O_(7)xx 100)/("Mass of compound") 0.12 gm of and organic compound containing phosphorus gave 0.22 gm of Mg_(2)P_(2)O_(7) by the usual analysis. Calculate the percentage of phosphorus in the compound.