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Prove that the area of a rhombus is equal to half the rectangle contained by its diagonals. Given: A rhombus `A B C D` such that its diagonals `A C\ a n d\ B D` intersect at `Odot` To Prove: `a r\ (r hom b u s\ A B C D)=1/2` (area of the rectangle contained by its diagonals `=1/2(A C\ x\ B D)`

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