If the area of a triangle with vertices `(-3,0),(3,0)` and `(0,0` is 9 sq. units. Then the value of `k` will be

The area of a triangle with vertices (-3,0) , (3,0) and (0,k) is 9 sq. Units. Then , then value of k will be

If the area of triangle with vertices (-3,0), (3,0) and (0,k) is 9 sq . units then the value of k is

The area of a triangle with vertices (-3,0),(3,0) and (0,k) is 9 sq. units. The value of 'k' will be

The area of a triangle with vertices (-3,0),(3,0) and (0,k) is 9 sq. units . The value of k will be :

IF the area of a triangle with vertices (-3,0) (3,0) and (0,k) is 9 sq units. Then find k.

The area of a triangle with vertices (-2,0),(0,k) and (0,4) is 4 square units.Then the values of K will be

The area of a triangle with vertices A(-3,0), B(3,0) and (0,k) is 9 sq. units . The value of k will be "........."

Area of the triangle with vertices (k,0),(1,1) and (0,3) is 5 sq. units. Find the values of k.