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BALAJI PUBLICATION-निश्चित समाकलन -स्वमूल्यांकन परीक्षण
- int(0)^(pi//2)cos^(2)xdx
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- int(0)^(pi//2)(sqrt(sinx))/(sqrtsinx +sqrtcosx)dx
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- int(0)^(pi//2)(sin^(3//2)x dx)/(sin^(3//2)x+cos^(3//2))dx
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- int(0)^(pi//2)(cos^(5)xdx)/(sin^(5)x+cos^(5)x)
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- int(-5)^(5)|x+2|dx
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- int(2)^(8)|x-5|dx
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- int(0)^(1)x(1-x)^(n)dx
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- int(0)^(pi//4)log(1+tanx)dx
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- int(0)^(2)x sqrt(2-x)dx
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- int(0)^(pi//2)(2log sin x-log sin 2x)dx
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- int(-pi//2)^(pi//2)sin^(2)xdx
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- int(0)^(pi)(xdx)/(1+sinx)
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- int(-pi//2)^(pi//2)sin^(7)xdx
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- int(0)^(2pi)cos^(5)xdx
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- int(0)^(pi//2)(sinx-cosx)/(1+sinx cosx)dx
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- सिद्ध कीजिए कि int(0)^(2)(sqrtx)/(sqrtx+sqrt(2-x))dx=1
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- सिद्ध कीजिए कि int(0)^(2a)(f(x))/(f(x)+f(2a-x))dx=a
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- सिद्ध कीजिए कि int(0)^(2pi)(x cos x)/(1+cosx)dx=2pi^(2)
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- सिद्ध कीजिए कि int(0)^(pi//2)(sqrt(secx))/(sqrt(secx)+sqrt("cosec x"))...
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- सिद्ध कीजिए कि int(-pi)^(pi)(cos^(2)x)/(1+a^(x))dx, a gt 0 =(pi)/(2)
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