Two years ago, a father was five times as old as his son. Two years later, his age will be 8 more than three times the age of the son. Find the present ages of father and son.

Two years ago,a father was five xx as old as his son.Two years later,his age will be 8 more than three xx the age of the son.Find the present ages of father and son.

Two years ago a father was five times as old as his son. Two years later, his age will be 8 years more than three times the age of the son. Represent this situation algebraically and graphically .

Four years ago, age of a person was 4 times that of his son. Six years later, the age of the person will be 10 years less than thrice the age of his son. Find the present ages of the person and his son

The age of a father 8 years ago was 5 times that of his son 8 years. Hence, his age will be 8 years more than twice the age of his son. Then the present age of fatherd is ………years.

The present age of father is four times the age of his son. After 10 years, age of father will become three times the age of his son. Find their present ages.

Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.

Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.

A father is three times as old as his son. After twelve years, his age will be twice as that of his son then. Find their present ages.