(18)/(2)*(5x-2)/(1+2x+3x^(2))

Add :5x^(2)-(1)/(3)x+(5)/(2),-(1)/(2)x^(2)+(1)/(2)x-(1)/(3) and -2x^(2)+(1)/(5)x-(1)/(6)

Simplify: (x^(2)-3x+2)(5x-2)-(3x^(2)+4x-5)(2x-1)

underset(x to oo)lim (3x^(2)+5x+2)/(2x^(2)-3x+1)=

The equation |{:((1+x)^(2),(1-x)^(2),-(2+x^(2))),(2x+1,3x,1-5x),(x+1,2x,2-3x):}|+|{:((1+x)^(2),2x+1,x+1),((1-x)^(2),3x,2x),(1-2x,3x-2,2x-3):}|=0

lim_(x->0)((1+5x^2)/(1+3x^2))^(1//x^2)=____

lim_(x rarr0)((1+5x^(2))/(1+3x^(2)))^(1/x^(2))=

lim_( x to 0) ((1+5x^(2))/(1+3x^(2)))^(1//x^(2)) = … .