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[" 4.For an elementary reaction "2Ak(1)=...

[" 4.For an elementary reaction "2Ak_(1)=(k_(1))/(k_(2))B" .the rate of disap- "],[" pearance of "A" is equal to: "],[[" (A) "(2k_(1))/(k_(2))[A]^(2)," (B) "-2k_(1)[A]^(2)+2k_(2)[B]],[" (C) "2k_(1)[A]^(2)-2k_(2)[B]," (D) "(2k_(1)-k_(2))[A]]]

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