यदि `a+b+c=0`, तो दिखाइए कि `a^(3)+b^(3)+c^(3)=3abc`.

If a+ b + c = 0 , show that : a^(3) + b^(3) + c^(3)= 3abc

(a^(3)+b^(3)-c^(3)+3abc)/(a+b-c)=

If a^(3)+b^(3)+c^(3)=3abc and a+b+cne0 , then

If a + b + c = 0 , show that a^(3) + b^(3) + c^(3) = 3abc The following are the steps involved in showing the above result. Arrange them in sequential order (A) a^(3) + b^(3) + 3ab (-c) = -c^(3) (B) (a + b)^(3) = (-c)^(3) (C) a + b + c = 0 rArr a + b = -c (D) a^(3) + b^(3) + 3ab (a +b) = -c^(3) (E) a^(3) + b^(3) + c^(2) = 3abc

If a+b+c= 0 find a^(3) + b^(3) + c^(3) + 3abc

If a+b+c=0 then prove that a^(3)+b^(3)+c^(3)=3abc

If a + b + c = 0 , then prove that a^(3)+b^(3)+c^(3)=3abc

If a, b c are real and a^(3)+b^(3)+c^(3) =3abc and a+b+c ne0 , then the relation between a, b,c will be