If the circle `x^2+y^2+2x+3y+1=0` cuts `x^2+y^2+4x+3y+2=0` at `Aa n dB` , then find the equation of the circle on `A B` as diameter.

If the circle x^2+y^2+2x+3y+1=0 cuts x^2+y^2+4x+3y+2=0 at A and B , then find the equation of the circle on A B as diameter.

If the circle x^2+y^2+2x+3y+1=0 cuts x^2+y^2+4x+3y+2=0 at A and B , then find the equation of the circle on A B as diameter.

If the circle x^2+y^2+2x+3y+1=0 cuts x^2+y^2+4x+3y+2=0 at A and B , then find the equation of the circle on A B as diameter.

If the circle x^(2)+y^(2)+2x+3y+1=0 cuts x^(2)+y^(2)+4x+3y+2=0 at A and B ,then find the equation of the circle on AB as diameter.

If the circle x^2+y^2+2x+3y+1=0 cuts another circle x^2+y^2+4x+3y+2=0 in A and B , then the equation of the circle with AB as a diameter is

The circle x^(2)+y^(2)=4 cuts the circle x^(2)+y^(2)+2x+3y-5=0 in A and B ,Then the equation of the circle on AB as diameter is

The circle x^2+y^2=4 cuts the circle x^2+y^2+2x+3y-5=0 in A and B , Then the equation of the circle on AB as diameter is

The circle x^(2)+y^(2)=4 cuts the circle x^(2)+y^(2)+2x+3y-5=0 in A &B. Then the equation of the circle on AB as a diameter is:

The straight line x+y - 1= 0 cuts the circle x^(2) + y^(2) - 6x - 8y = 0 at A and B. Find the equation of the circle of which AB is a diameter.