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0.1 M K(4)[Fe(CN)(6)] is 50% ionised in ...

0.1 M `K_(4)[Fe(CN)_(6)]` is 50% ionised in aqueous medium. What will be its van't Hoff factor ?

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The electrolyte solutions show abnormal colligative porperties.To account for this effect we define a quantity called the Van't Hoff factor given by i=("Actual number of particles in solution after dissociation")/("Number of formula units initially dissolved in solution") i=1 ("for non-electrolytes") igt1 ("for electrolytes, undergoing dissociation") ilt1 ("for solutes, undergoing association") Answer the following questions: 0.1 M K_(4)[Fe(CN)_(6)] is 60% ionized. What will be its Van't Hoff factor?

The electrolyte solutions show abnormal colligative porperties.To account for this effect we define a quantity called the Van't Hoff factor given by i=("Actual number of particles in solution after dissociation")/("Number of formula units initially dissolved in solution") i=1 ("for non-electrolytes") igt1 ("for electrolytes, undergoing dissociation") ilt1 ("for solutes, undergoing association") Answer the following questions: 0.1 M K_(4)[Fe(CN)_(6)] is 60% ionized. What will be its Van't Hoff factor?

The electrolyte solutions show abnormal colligative porperties.To account for this effect we define a quantity called the Van't Hoff factor given by i=("Actual number of particles in solution after dissociation")/("Number of formula units initially dissolved in solution") i=1 ("for non-electrolytes") igt1 ("for electrolytes, undergoing dissociation") ilt1 ("for solutes, undergoing association") Answer the following questions: 0.1 M K_(4)[Fe(CN)_(6)] is 60% ionized. What will be its Van't Hoff factor?

K_(2)HgI_(4) is 40% ionised in aqueous solution. The value of its van't Hoff factor (i) is :

K_(2)HgI_(4) is 40% ionised in aqueous solution. The value of its van't Hoff factor (i) is :

0.1M K_(4) [Fe (CN)_(6)] is 60% ionized.What will be its Van't Hoff factor?

K_(2)HgI_(4) is 55% ionized in aqueous solution. The value of Van't Hoff factor is

K_(2)HgI_(4) is 55% ionized in aqueous solution. The value of Van't Hoff factor is

A decimolar solution of potassium ferrocyanlde K_(4) [Fe(CN)_(6)] is 50% dissociated at 3001K. Calculate the value of Van't Hoff factor for postuslum ferrocyanide.

If Hg_(2)Cl_(2) is 100% ionised, then find out its van't Hoff factor.