S. IF F(X) = 1+ xtanx»x (0.5), then(A) f(x) has exactly one point of minima(B) f(x) has exactly one point of maxima(C) f(x) is increasing in(D) maxima occurs at x, where xo = cosx,

f(x) = (x)/(1 + x tan x), x in (0, (pi)/(2)) then a)f(x) has exactly one point of minima b)f(x) has exactly one point of maxima c)f(x) is increasing in (0, (pi)/(2)) . d)f(x) is decreasing in (0, (pi)/(2)) .

If f(x)=(x)/(x+tan x),x belongs to (0,pi/2)(A)f(x) has exactly one point of maxima (C) f(x) is increasing in (0,pi/2))((B)f(x) has exactly one point of minima (D) none of these

Column I Column II f(x)=x^2logx f(x) has one point of minima f(x)=x(log)_e x q. f(x) has one point of maxima f(x)=(logx)/x r. f(x) increase x in (0,e) f(x)=x^(-x) s. f(x) decrease x in (0,1/e)

f(x)={((pi)/(2)+x)(x =(pi)/(4)) then (A)f(x) has no point of local maxima

If f(x)=x^3+b x^2+c x+d and 0

Let f (x) = x^(2) , x in [-1 , 2) Then show that f(x) has exactly one point of local minima but global maximum is not defined.

Let f(x) =x^(2) , x in (-1,2) Then show that f(x) has exactly one point of local minima but global maximum Is not defined.

consider the function f(X) =x+cosx -a values of a which f(X) =0 has exactly one positive root are

consider the function f(X) =x+cosx -a values of a which f(X) =0 has exactly one positive root are