If `theta=pi/(4n)` then the value of `tanthetatan(2theta)tan(3theta)....tan((2n-1)theta)` is

If theta=pi//4n , then the value of tan(theta) tan (2theta).....tan(2n-2)thetatan(2n-1)theta is

tantheta+tan2theta=tanthetatan2theta=1

If tan theta=(pi)/(7) then find the value of (tan theta.tan2 theta+tan2 theta tan4 theta+tan4 theta*tan theta) is....

Solve the equation: tantheta+tan2theta+tanthetatan2theta=1

If tantheta+tan2theta+tanthetatan2theta=1 then theta equals to

Solve : tantheta+tan2theta+tan3theta=tanthetatan2thetatan3theta

Show that: If theta=(2 pi)/(7), prove that tan theta tan2 theta+tan2 theta tan4 theta+tan4 theta tan theta=

If: tantheta + tan 2theta + tan 3theta = tan theta.tan2theta.tan 3theta , then: theta =