In a room, there are `6` couples. Out of them if `4` are chosen at random the probability that they may be `2` couples is (A) `2/33` (B) `1/33` (C) `1/66` (D) `32/33`

A positive integer is chosen at random the probability that the sum of the digits of its square is 39 is (A) 1/33 (B) 2/33 (C) 1/11 (D) Zero

A positive integer is chosen at random . The probability that sum of the digits of its square is 33 is :

S={1,2,3,....20} if 3 numbers are chosen at random from S, the probability for they are in A.P.is (A) (3)/(38) (B) (35)/(33) (C) (33)/(35) (D) (1)/(38)

Six married couples are locked in a room, If two people are chosen at random, then the probability that one is male and the other is a female is

Six married couples are locked in a room, If two people are chosen at random, then the probability that one is male and the other is a female is

A bag contains 3 red, 4 white and 5 blue balls. If two are drawn at random, then the probability that they are of different colours, is a) (47)/(66) b) (23)/(33) c) (47)/(132) d) (47)/(33)

6 married couples are standing in a room.If 4 people are chosen at random,then the chance that exactly one married couple is among the 4 is-

There are 5 positive numbers and 6 negative numbers. Three numbers are chosen at random and multiplied. The probability that the product being a negative number is a) (11)/(34) b) (17)/(33) c) (16)/(35) d) (16)/(33)