A particle is projected from the bottom of an inclined plane of inclination `30^@` with velocity of `40 m//s` at an angle of `60^@` with horizontal. Find the speed of the particle when its velocity vector is parallel to the plane. Take `g = 10 m//s^2`.

A ball is projected from the bottom of an inclined plane of inclination 30^@ , with a velocity of 30 ms^(-1) , at an angle of 30^@ with the inclined plane. If g = 10 ms^(-2) , then the range of the ball on given inclined plane is

A ball is projected from the bottom of an inclined plane of inclination 30^@ , with a velocity of 30 ms^(-1) , at an angle of 30^@ with the inclined plane. If g = 10 ms^(-2) , then the range of the ball on given inclined plane is

A particle is projected from the bottom of an inclined plane of inclination 30^@ . At what angle alpha (from the horizontal) should the particle be projected to get the maximum range on the inclined plane.

A particle is projected from the bottom of an inclined plane of inclination 30^@ . At what angle alpha (from the horizontal) should the particle be projected to get the maximum range on the inclined plane.

A particle A is projected from the ground with an initial velocity of 10m//s at an angle of 60^(@) with horizontal. From what height should an another particle B be projected horizontally with velocity 5m//s so that both the particles collide in ground at point C if both are projected simultaneously g=10 m//s^(2) .

A particle A is projected from the ground with an initial velocity of 10m//s at an angle of 60^(@) with horizontal. From what height should an another particle B be projected horizontally with velocity 5m//s so that both the particles collide in ground at point C if both are projected simultaneously g=10 m//s^(2) .

A particle is projected upwards with a velocity of 100 m//s at an angle of 60^(@) with the vertical. Find the time when the particle will move perpendicular to its initial direction, taking g = 10 m//s^(2) .

A particle is projected upwards with a velocity of 100 m//s at an angle of 60^(@) with the vertical. Find the time when the particle will move perpendicular to its initial direction, taking g = 10 m//s^(2) .