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[" Let "P" be the point on the parabola,"y^(2)=8x," which is at a "],[" minimum distance from the centre "C" of the circle,"],[x^(2)+(y+6)^(2)=1." Then,the equation of the circle,passing "],[" through "C" and having its centre at "P" is "],[" (a) "x^(2)+y^(2)-4x+8y+12=0],[" (b) "x^(2)+y^(2)-x+4y-12=0],[" (c) "x^(2)+y^(2)-(x)/(4)+2y-24=0],[" (d) "x^(2)+y^(2)-4x+9y+18=0]

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Let P be the point on the parabola, y^(2)=8x which is at a minimum distance from the center C of the circle , x^(2)+(y+6)^(2)=1 . Then the equation of the circle, passing through C and having its canter at P is

Let P be the point on the parabola, y^2=8x which is at a minimum distance from the centre C of the circle,x^2+(y+6)^2=1. Then the equation of the circle, passing through C and having its centre at P is : (1) x^2+y^2-4x+8y+12=0 (2) x^2+y^2-x+4y-12=0 (3) x^2+y^2-x/4+2y-24=0 (4) x^2+y^2-4x+9y+18=0

Let P be the point on the parabola, y^2=8x which is at a minimum distance from the centre C of the circle, x^2+(y+6)^2=1. Then the equation of the circle, passing through C and having its centre at P is : (1) x^2+y^2-4x+8y+12=0 (2) x^2+y^2-x+4y-12=0 (3) x^2+y^2-x/4+2y-24=0 (4) x^2+y^2-4x+9y+18=0

Let P be the point on the parabola, y^2=8x which is at a minimum distance from the centre C of the circle, x^2+(y+6)^2=1. Then the equation of the circle, passing through C and having its centre at P is : (1) x^2+y^2-4x+8y+12=0 (2) x^2+y^2-x+4y-12=0 (3) x^2+y^2-x/4+2y-24=0 (4) x^2+y^2-4x+9y+18=0

Let P be the point on the parabola, y^2=8x which is at a minimum distance from the centre C of the circle, x^2+(y+6)^2=1. Then the equation of the circle, passing through C and having its centre at P is : (1) x^2+y^2-4x+8y+12=0 (2) x^2+y^2-x+4y-12=0 (3) x^2+y^2-x/4+2y-24=0 (4) x^2+y^2-4x+9y+18=0

Let P be the point on the parabola, y^2=8x which is at a minimum distance from the centre C of the circle, x^2+(y+6)^2=1. Then the equation of the circle, passing through C and having its centre at P is : x^ 2 + y^ 2 − x + 4 y + 12 = 0 x^ 2 + y^ 2 − x/ 4 + 2 y − 24 = 0 x^ 3 + y^ 2 − 4 x + 9 y − 18 = 0 x^ 2 + y^ 2 − 4 x + 8 y + 12 = 0

The coordinates of the point on the parabola y^2=8x which is at a minimum distance from the circle x^2+(y+6)^2=1 are

Find the coordinates of a point on the parabola y^2 = 8x which is at minimum distance from the circle x^2 + (y + 6)^2 =1