A 0.2 F capacitor was charged with a 600 V battery. On removing the battery, it is connected to another capacitor whose capacitance. F is the given potential voltage (a) 100V (b) 120V (0) 300V (d) 6000

0.2 F capacitor is charged to 600 V by a battery. On removing the battery it is connected with another parallel plate condenser of 1 F . The potential decreases to

0.2 F capacitor is charged to 600 V by a battery. On removing the battery it is connected with another parallel plate condenser of 1 F . The potential decreases to

A 600pF capacitor is charged with 100 V battery . Calculate the energy stored and charge on the capacitor .

A 800 muF capacitor is charged by a 100V battery. After some time, the battery is disconnected. The capacitor is then connected to another 800muF capacitor. What is the electrostatic energy stored ?

A capacitor of capacitance 700 pF is charged by 100 V battery. The electrostatic energy stored by the capacitor is

A capacitor of capacitance 700 pF is charged by 100 V battery. The electrostatic energy stored by the capacitor is

A 600pF Capacitor is connected with a 200V battery .After removing the battery another 300 pF capacitor is connected with 600 pF capacitance. The second-capacitor was uncharged. What will be the common potential?

A 100 mu F capacitor is charged to a potential difference of 24 V . It is connected to an uncharged capacitor of capacitance 20 mu F What will be the new potential difference across the 100 mu F capacitor?