[" 5.If "2sin^(2)theta-cos^(2)theta=2," then "theta=?],[[" (c) "0^(@)," (b) "30^(@)],[" (c) "60^(@)," (d) "90^(@)]]

If 2sin^(2)theta-cos^(2)theta=2, find the value of theta

If 2sin^2theta-cos^2theta=2, find the value of theta.

For ninz,2sin^(2)theta=cos2theta implies theta//2 =

If A=[cos2 theta sin2 theta-sin2 theta cos2 theta], find A^(2)

If cos theta+cos^(2)theta=1 then sin^(2)theta+2sin^(2)theta+sin^(2)theta=

2(cos theta+cos2 theta)+(1+2cos theta)sin2 theta=2sin theta

If f(theta)=(1-sin2 theta+cos2 theta)/(2sin2 theta) then value of f(11^(@))*f(34^(@)) is

If |(1+sin^(2)theta, cos^(2)theta, 4 sin 2 theta),(sin^(2) theta, 1+cos^(2)theta, 4sin2 theta),(sin^(2)theta, cos^(2)theta, 4 sin 2 theta-1)|=0 and 0 lt theta lt (pi)/2 then cos 4 theta=

If A=[[cos 2 theta, sin 2 theta],[-sin2theta, cos2theta]] , find A^2

If A=[[cos 2 theta, sin 2 theta],[-sin2theta, cos2theta]] , find A^2