m women and n men are too be seated in a row so that no two men sit together. If `mgtn` then show that the number of wys in which they can be seated is `(m!(m+1)!)/((m-n+1)!)`

m men and n women are to be seated in a row so that no two women sit together. If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!) .

m men and n women are to be seated in a row so that no two women sit together.If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!)

m men and n women are to be seated in a row so that no two women sit together. If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!) .

m men and n women are to be seated in a row so that no two women sit together. If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!) .

m men and n women are to be seated in a row that no two women sit together . If m gt n, then show that the mumber of ways in which they can be sated is (m!(m+1)!)/((m-n+1)!)

If n men and m women are to be seated in a row so that no two women sit together . If ngtm , then show that number of ways in which they can be seated is (n!(n+1)!)/((n-m+1)!)

m men and w women are to be seated in a row so that no two women sit together.If m>w then the number of ways in which they can be seated is

m' men and 'n' women are to be seated in a row so that no two women sit next to each other. If mgen then the number of ways in which this can be done is