Home
Class 12
MATHS
Show that the equation of the circle des...

Show that the equation of the circle described on the chord intercepted by the parabola `y^2=4ax` on the line `y = max + c` as diameter is `m^2(x^2+y^2)+2x(mc -2a) -4amy +4amc + c^2 =0`.

Promotional Banner

Similar Questions

Explore conceptually related problems

Length of the chord intercepted by the parabola y^(2)=4ax on the line y=mx+c is :((4)/(m^(2)))sqrt(a(1+m^(2))(a+mc))

The locus of the centre of the circle described on any focal chord of the parabola y^(2)=4ax as the diameter is

The locus of the centre of the circle described on any focal chord of the parabola y^(2)=4ax as the diameter is

Find the equation of the circle described on the line segment joining the foci of the parabolas x^2 - 4ay and y^2 = 4a(x-a) as diameter.

The equation of the circle described on the common chord of the circles x^2 +y^2- 4x +5=0 and x^2 + y^2 + 8y + 7 = 0 as a diameter, is

The equation of the circle described on the chord 3x+y+5=0 of the circle x^(2) +y^(2) =16 as diameter is

The equation of the circle described on the common chord of circles x^2+y^2-8x+y-15=0 and x^2+y^2-4x+4y-42=0 as diameters is :

Find the equation of the circle described on the line segment as diameter joining the foci of the parabolas x^2 =4ay and y^2 = 4a(x-a) as diameter.