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In a Delta ABC, a (cos^2 B+ cos^2 C)+cos...

In a `Delta ABC`, `a (cos^2 B+ cos^2 C)+cos A (c cos C+b cos B)` is equal to

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Knowledge Check

  • With usual notations, in triangle ABC, a cos (B - C) + b cos (C - A) + c cos (A - B) is equal to

    A
    `(abc)/(R^(2))`
    B
    `(abc)/(4R^(2))`
    C
    `(4 abc)/(R^(2))`
    D
    `(abc)/(2R^(2))`

  • In Delta ABC, a^(3) cos (B-C) +b^(3) cos (C-A) +c^(3) cos (A-B) is equal to

    A
    3abc
    B
    2abc
    C
    abc
    D
    5abc

  • In a triangle ABC, cos A + cos B + cos C

    A
    `lt 1`
    B
    `gt 1`
    C
    `gt 1` but no` gt 2`
    D
    `gt 1` but not `gt 3//2`

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    In a Delta ABC if (cos A)/(b cos C+c cos B)+(cos B)/(c cos A+a cos C)+(cos C)/(a cos B+b cos A)=(a^(2)+b^(2)+c^(2))/(Kabc) then K^(k) is equal to

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    In Delta ABC, (cos C+ cos A)/(c+a)+(cos B)/b=

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