Suppose the parabola (y- k)^2= 4 (x - h...

Suppose the parabola `(y- k)^2= 4 (x - h)`, with vertex A, passes through `O=(0,0) and L = (0,2)`. Let D be an end point of the latus rectum. Let the y-axis intersect the axis of the parabola at P. Then `/_PDA` is equal to

Similar Questions

Explore conceptually related problems

The end points of the latus rectum of the parabola x ^(2) + 5y =0 is

The point of intersection of the latus rectum and the axis of the parabola y^(2)+4 x+2 y-7=0 is

Find the vertex, focus, latus-rectum, axis and directrix of the parabola x^2- y - 2x = 0 .

Find the vertex, focus, latus-rectum axis and directrix of the parabola x^(2) - y - 2x = 0.

Suppose that a parabola has vertex (0,4) and focus (0,2) Is y-axis the axis of the parabola?

A parabola with vertex (2,3) and axis parallel toy-axis,passes through (4,5). Then length of its latus rectum is

The end points of latus rectum of the parabola x^2+4x-8y+12=0 are _____.

The tangents drawn at end points of latus rectum of parabola S=0 intersect at (1,1) and (3,2) is its focus.Then axis of parabola S=0 is