A particle starts simple harmonic motion from the mean position. Its amplitude is a and total energy E . At one instant its kinetic energy is 3E/4 . Its displacement at that instant is

A particle starts simple harmonic motion from the mean position. If It's amplitude is A and time period T, then at a certain instant, its speed is half of its maximum speed at this instant, the displacement is

A particle starts simple harmonic motion from the mean position. Its amplitude is a and time period is T. what is its displacement when its speed is half of its maximum speed?

A body executing SHM has a total energy E . When its kinetic energy is 3E//4 , the displacement of the particle is (A is amplitude)

In a simple harmonic motion, when the displacement it one- half of the amplitude, what fraction of the total energy (E) is kinetic ?

For a particle executing simple harmonic motion, find the distance from the mean position at which its potential and kinetic energies are equal.

A particle is executing simple harmonic motion. Its total energy is proportional to its

A particle executives simple harmonic motion of amplitude A. The distance from the mean position where its kinetic energy is equal to its potential energy is