In YDSE, the two slits are separated by 0.1 mm and they are
0.5 m from the screen. The wavelength of light used is 5000 Å. Find the distance
between 7th maxima and 11 th mimima on the upper side of screen.

In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m from the screen. The wavelenght of light used is 5000A^(0) . Find the distance between 7th maxima 11th minima on the screen.

In YDSE, the two slits are separated by 0 . 1 m m and they are 0.5 m from the screen . The wavelengh of light used is 5000 Å . What is the di stance between 7^(th) minima on screen ?

In a biprism experiment, the distance between the two virtual sources is 0.1 mm and the screen is placed at 100 cm from the slits. If the wavelength of light used is 5000 Å, then the distance of the 4th bright band from the central bright band will be

In the youngs double slit experiment ,the slit sepration is 1mm ,the distance between source and screen is 1m ,wavelength of light used is 6500 angstrom.Find the distance between fifth maxima and third minima in (mm)?

In Young's double-slit experiment, the slit separation is 0.5 mm and the screen is 0.5 m away from the slit. For a monochromatic light of wavelength 500 nm, the distance of 3rd maxima from the 2nd minima on the other side of central maxima is

In Young's double-slit experiment, the slit separation is 0.5 mm and the screen is 0.5 m away from the slit. For a monochromatic light of wavelength 500 nm, the distance of 3rd maxima from the 2nd minima on the other side of central maxima is

In YDSE, the distance between the slits is 1 m m and screen is 25cm away from the slits . If the wavelength of light is 6000 Å , the fringe width on the secreen is