If the line `(x-1)/2=(y+3)/1=(z-5)/(-1)` is parallel to the
plane `px + 3y - z + 5 = 0 `, then the value of p -

If the line (x+1)/3=(y-2)/4=(z+6)/5 is parallel to the planes 2x-3y+kz=0 , then the value of k is

The image of the line (x-1)/(3) = (y-3)/(1) = (z-4)/(-5) in the plane 2x - y + z + 3 =0 is the line

If line (x-2)/(3)=(y-4)/(4)=(z+2)/(1) is parallel to planes mux+3y-2z+d=0 and x-2lambda y+z=0 , then value of lambda and mu are

The image of the line (x -1)/(3) = (y -3)/(1) = (z -4)/(-5) in the plane 2x - y + z + 3=0 is the line-

Proved that the line (x-1)/2=(y+2)/(-3)=(z-3)/1 lies on the plane 7x+5y+z=0

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line

The image of the line (x-1)/(3) = (y-3)/(1) = (z-4)/(-5) in the plane 2x - y + z + 3 = 0 is the line ..............

Find p if the plane x+y-2z+6=0 is parallel to the plane px+3y-6z-1=0.