[" If "tan A=(1)/(3)" and "tan B=1/2],[" Gind "tan(A+B)=(tan A+tan B)/(1-tan A times tan B)],[" Find "A times B]

tan(A+B)=(tan A+tan B)/(1-tan A tan B)

If tan A=(1)/(2) and tan B=(1)/(3), then tan(2A+B) is

If A and B are acute angles such that tan A=(1)/(2),tan B=(1)/(3) and tan(A+B)=(tan A+tan B)/(1-tan A tan B), find A+B

If tan A=1/2 and tan B=1/3 , then tan(A +B) is equal to

If tan A=-(1)/(2) and tan B=-(1)/(3) then A+B=

If tan A=1/2 and tan B=1/3 , then: A+B=

Calculate A+B when tan A=(2)/(3) and tan B=(3)/(2) if it is given that tan(A+B)=(tan A+tan B)/(1-tan A tan B) where A and B are acute angles.

If A=60⁰ and B=30⁰ , verify that tan (A+B)=(tan A+tan B)/(1-tan A tan B)

If A=60⁰ and B=30⁰ , verify that tan (A-B)=(tan A-tan B)/(1+tan A tan B)