A pendulum of mass 1 kg and length  = 1m is released from rest at angle  = 60º. The power delivered by all the forces acting on the bob at angle  = 30º will be: (g = 10 m/s2)

A pendulum of length  = 1 m is released from 0 = 60º. The rate of change of speed of the bob at  = 30º is: (g = 10 m/s2)

A pendulum of length l=1m is released from theta_(0)=60^(@) . The rate of change of speed of the bob at theta=30^(@) is.

A pendulum of length l=1m is released from theta_(0)=60^(@) . The rate of change of speed of the bob at theta=30^(@) is.

A pendulum of length l=1m is released from theta_(0)=60^(@) . The rate of change of speed of the bob at theta=30^(@) is.

A pendulum bob of mass m and length L is released from angle theta with the vertical. Find (a) the speed of the bob at the bottom of the swing and (b) tension in the string at that time

A block of mass 2 kg rests on an inclined plane of inclination angle 37^(@) , then calculate the force of friction acting on the block [ take g = 10 m//s^(2))