What should be minimum length of an open organ pipe for producing a note of 110 Hz. The speed of sound is `330 ms^(-1)`.

A pipe is open at both ends and 40 cm of its length is in resonance with an external frequency 1.1 kHz. If the speed of sound is 330ms^(-1) , which harmonic is in resonance?

A closed pipe and an open pipe produce simultaneously a sound with 5 beats per second. If the length of the open pipe is 30 cm, then determint the required change in the length of the closed pipe if both the pipes are to produce the sound of same frequency. Speed of sound is 330 ms^(-1) .

Two adjacent resonance frequency of an open organ pipe are 1800 and 2100 Hz . Find the length of the tube. The speed of sound in air is 330 m//s .

A pipe of 30 cm long and open at both the ends produces harmonics. Which harmonic mode of pipe resonates a 1.1 kHz source ? Given speed of sound in air =330 ms^(-1) .

If the length of an open organ pipe is 33.3 cm, then the frequency of fifth overtone is (v_(sound)=333ms^(-1))

The frequency of fundamental tone in an open organ pipe of length 0.48 m is 320 Hz. Speed of sound is 320 m/sec. Frequency of fundamental tone in closed organ pipe will be

A closed pipe and an open pipe sounding together produce 5 beats per second. If the length of the open pipe is 30 cm, find by how much the length of the closed pipe should be changed to bring the two pipes in unison. Take speed of sound in air is 330 m/s.