Illustration 19 2 11.107 Y UI NUH Will be present in = = 10-3 * 1.184 = 197.33 mL What weight of Na, CO, of 85% purity would be required to prepare 45.6 mL of 0.235N H,SO, ? Meq. of Na,Co, = Meq. of H,80, = 45.6 x 0.235 Solution WNa, CO3 W Na2CO3 x 10 ENa2CO3 azCO3 x 1000 = 45.6 x 0.235 000 = 45.6 x 0.235 106/2 .. Wna.co= 0.5679 g For 85 g of pure Na,CO2, weighed sample = 100 g .. For 0.5679 g of pure Na,CO2, weighed sample = x0.5679 = 0.6681 g AM that will مهما اه اه o burnlato in