Home
Class 12
PHYSICS
[" (ii) "A" uniform electric field "],[E...

[" (ii) "A" uniform electric field "],[E=E_(x)hat iN/C" for "x>0" and "],[E=-E_(x)hat iN/C" for "x<0" are given "],[" A right circular cylinder of "],[" length "l" cm and radius "r" cm has "],[" its centre at the "X" -axis.Find out "],[" axis along the "X" -axis.Find out "],[" axis along the "X" -axis.Find out "],[" the net outward flux.Using the "],[" Gauss' law,the net charge "],[" expression for the net charge "],[" or in thin the cylinder.I Dehlizoosc "]

Promotional Banner

Similar Questions

Explore conceptually related problems

A right circular cylinder of length L (in m) and of radius R (in m) has its center at the origin and its length along the X-axis. A uniform electric field vecE = E_x hat I N C^-1 for x > 0 and vec E = -E_xhati NC^-1 for x < 0 exists over the cylinder. Find net outward electric flux

A uniform electric field is given as [E = 100 hat(i) N//C] for x gt 0 and E- 100 hat(i) N//C for x lt 0 . A right circular cylinder of length 20 cm and radius 5cm has its centre at the origin and its axis along the X-axis, so that one face is at x= +10 cm and other is at x= -10 cm. What is the net outward flux through each flat face?

A uniform electric field is given as [E = 100 hat(i) N//C] for x gt 0 and E- 100 hat(i) N//C for x lt 0 . A right circular cylinder of length 20 cm and radius 5cm has its centre at the origin and its axis along the X-axis, so that one face is at x= +10 cm and other is at x= -10 cm. What is the flux through the side of cylinder?

A uniform electric field is given as [E = 100 hat(i) N//C] for x gt 0 and E- 100 hat(i) N//C for x lt 0 . A right circular cylinder of length 20 cm and radius 5cm has its centre at the origin and its axis along the X-axis, so that one face is at x= +10 cm and other is at x= -10 cm. What is the net outward flux through the cylinder?

" A uniform electric field "bar(E)-E_(x)i+E_(y)j" exists.If the points "(1,0)" and "(-1,4)" are equipotential,"(E_(x))/(E_(y))" is equal to "-

A cube of side a is placed in a uniform electric field E = E_(0) hat(i) + E_(0) hat(j) + E_(0) k . Total electric flux passing through the cube would be

A cube of side a is placed in a uniform electric field E = E_(0) hat(i) + E_(0) hat(j) + E_(0) k . Total electric flux passing through the cube would be

A thin non-conducting ring or radius a has a linear charge density lambda = lambda_(0) sin phi . A uniform electric field E_(0) hat(i) + E_(0) hat(j) exist in the region . .Net torque acting on ring is given as :

A thin non-conducting ring or radius a has a linear charge density lambda = lambda_(0) sin phi . A uniform electric field E_(0) hat(i) + E_(0) hat(j) exist in the region . .Net torque acting on ring is given as :