If the banking angle of curved road is given by `tan^(-1)((3)/(5))` and the radius of curvature of the road is 6 m, then the safe driving speed should not exceed (take, `g=10ms^(-2)`)

A road is banked with an angle 0.01 radian. If the radius of the road is 80 m (g = 10 m//s ^2) then the safe velocity for the drive will be

A road is banked at an angle of 0.01 radian. If the radius of the road is 80m, then safe speed for the driver will be: (g = 10 N kg^-1)

A road is banked with an angle 0.01 radian .If the radiaus of the road is 80m (g=10 m//s^(2)) then the safe velocity for the drive will be

For traffic moving at 60 kmh^(-1) , if the radius of the curve is 0.1 km , what is the correct angle of banking of the road? Take g = 10ms^(-2) .

Keeping the banking angle same , to increase the maximum speed with which a vehicle can traveln on the curve road by 10 % , the radius of curvature of the road has to be changed from 20 m to

Keeping the banking angle same, to increase the maximum speed with which a vehicle can travel on the curved road by 10%, the radius of curvature of the road has to be changed from 20 m to

Keeping the banking angle same, to increase the maximum speed with which a vehicle can travel on the curve road by 10 %, the radius of curvature of the road has to be changed from 20 m to

The banking angle for a curved road of radius 490 m for a vehicle moving at 35 ms^-1 is