`A` drop of water of volume `V` is pressed between the two glass plates so as to spread to an area. `A`. If `T` is the surface tension, the normal force required to separate the glass plates is

A drop of water of volume V is pressed between the two glass plates so as to spread on area A. If T is the surface tension, the normal force required to separate the glass plates is :

A drop of Volume V is pressed between the two glass plates so as to spread to an area of A . If T is the surface tension, the normal force required to separate the glass plates is

A water drop of 0.05 cm^(3) is squeezed between two glass plates and spreads into area of 40 cm^(2) . If the surface tension of water is 70 dyne cm^(-1) , then the normal force required to separate the glass plates from each other will be

A drop of water of volume 0.05cm^3 is pressed between two glass plates, as a consequence of which it spreads and occupies an area of 40cm^2 . If the surface tension of water is 70 dyne/cm, then the normal force required to separate out the two glass plates will be in newton)

A thin liquid film of thickness 5 xx 10^(-5) m is formed between two glass plates of surface area 1 xx 10^(-2) m^(2) , If the surface tension of the liquid is 60 xx 10^(-2) n/m the force that is required to separate the glass plates is

If a water drop is kept between two glass plates, then its shape is