" (d) "int_(0)^( pi)[log(1+cos x)]dx

int_(0)^((pi)/(2))log(cos x)dx=

Find I=int_(0)^( pi)ln(1+cos x)dx

int_(0)^( pi)(dx)/(1+cos x)

int_(0)^( pi)cos2x*log(sin x)dx

By using the properties of definite integrals, evaluate the integrals int_(0)^( pi)log(1+cos x)dx

Prove that, int_(0)^(pi)log(1+cos x)dx=-pi log2 , given int_(0)^((pi)/(2))log((sin x))dx=(pi)/(2)"log"(1)/(2) .

int_(0)^(2pi) ln (1+Cos x) dx=

Prove that: int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2

Prove that: int_(0)^(pi//2) log (sin x) dx =int_(0)^(pi//2) log (cos x) dx =(-pi)/(2) log 2

int_(0)^(pi)log(1+cosx)dx=-pi(log2)