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In the given figure, AB=14 cm, radius of...

In the given figure, AB=14 cm, radius of incircle of `DeltaABC` is 4 cm, AF=6 cm, AE=6 cm and BD=8 cm. Find AC and BC

Text Solution

Verified by Experts

Let `O` is the center of the incircle.
Then, in `Delta AOE`,
`OA^2= AE^2+OE^2`
Here, `OE = r = 4cm`
`:. OA^2 = 6^2+4^2 = 36+16=>OA^2 = 52`
As, `OA = OB = OC`
`:. OB^2 = OC^2 = 52`
Now, in `Delta COE`
...
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