A spectral line in the Lyman series of hydrogen atom has a wave number of `82200 cm^(-1)` .What transition is resposible for the radiation ? `(R = 109600 cm^(-1))`

A spectral line in the spectrum of H atom has a wave number of 1522.222 cm^(-1) .The transition responsible for this radiation is (Rydberg constant R = 10977 cm^(-1)

A spectral line in the spectrum of H atom has a wavelength of 15222.22 cm^(-1) .The transition responsible for this rediation is (Rydherg constant R = 10977 cm^(-1)

The shortest lambda for the Lyman series of hydrogen atom is _______(given R_H=109678 cm^-1 )

The limiting value of wave number in Lyman series of hydrogen atoms is:

A spectral line in the Balmer series of hydrogen spectrum corresponds to wavelength 6561Å. Find the energy levels involved in the transition responsible for the origin of this line (R=109679cm^(-1)) .

The wave number of the series limiting line for the Lyman series for hydrogen atom is (R = 109678 cm^-1 )

The wave number of the series limiting line for the Lyman series for hydrogen atom is (R =109678cm^(-1) )

The wave number of a specturm in Lyman series in hydrogen atom is 82260 cm^-1 . Show that this specturm is created by shifting the electron from second .to first orbit. [R = 109670 cm^-1]

The wave number of the first line in the Lyman series in hydrogen spectrum is