Find the point on the curve y=x/(1+x^2),...

Find the point on the curve `y=x/(1+x^2)`, where the tangent to the curve has the greatest slope.

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slope=`dy/dx=d/dx(x/(1+x^2))`
`=((1+x^2)*1-x(2x))/(1+x^2)^2`
`=(1-x^2)/(1+x^2)^2`
`dy/dx` is maximum when`(x/(1+x^2))^2` is minimum
`x=0,y=0`

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