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[quad (sin theta-csc theta)(cos theta-se...

[quad (sin theta-csc theta)(cos theta-sec theta)=(1)/(tan theta+cot theta)*" ICBEE "2009C," '10"],[" Thow We have "]

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Prove that (sin theta- "cosec" theta )(cos theta- sec theta )=(1)/(tan theta + cot theta).

Prove that (sin theta- "cosec" theta )(cos theta- sec theta )=(1)/(tan theta + cot theta).

Prove that (sin theta- "cosec" theta )(cos theta- sec theta )=(1)/(tan theta + cot theta).

Find ("cosec" theta-sin theta)(sec theta-cos theta)(tan theta+cot theta) :?

(sec theta+csc theta)^(2)-(tan theta+cot theta)^(2)=

cos ec theta(sec theta-1)-cot theta(1-cos theta)=tan theta-sin theta

(cosec theta -sin theta ) (sec theta - cos theta ) (tan theta + cot theta ) = 1.

(cot theta+csc theta-1)/(cot theta-csc theta+1)=(1+cos theta)/(sin theta)

cos ect theta(sec theta-1)-cot theta(1-cos theta)=tan theta-sin theta

tan theta/(1-cot theta)+cot theta/(1-tan theta)=1+sec theta cosec theta