Home
Class 12
PHYSICS
[" The temperature coefficient of resist...

[" The temperature coefficient of resistance of "],[" conductor varies as a(T) "=3T^(2)+2T" .If "R_(0)" is "],[" resistance at "T=0" and "R" is resistance at "T],[" then:- "],[(S)R=R_(0)(6T+2)],[" (2) "R=R_(0)(1+T^(2)+T^(3))],[R=R_(0)(1-T+T^(2)+T^(3))]

Promotional Banner

Similar Questions

Explore conceptually related problems

The temperature coefficient of resistance of conductor varies as alpha(T) = 3T^2 +2T. If R_0 is resistance at T = 0and R is resistance at T, then

The temperature coefficient of resistance of conductor varies as alpha(T) = 3T^2 +2T. If R_0 is resistance at T = 0and R is resistance at T, then

[" Temperature of a resistance at "],[" temperature "t^(0)C" is "R=R_(0)(1+at+bt^(2))" ."],[" Here "R_(0)" is the temperature at "0^(0)C" ,the "],[" temperature coefficient of resistance at "],[" temperature "t" is: "]

If r=t+2 and s+2=t , then sr=

The graph shows the variation of l nR v//s (1)/(T^(2)) , where R is resistance and T is temperature. Then find R as function T .

The graph shows the variation of l nR v//s (1)/(T^(2)) , where R is resistance and T is temperature. Then find R as function T .

The resistance t R of a conductor varies with temperature t as shown in the figure. If the variation is represented by R_(t) = R_(0)[1+ alphat +betat^(2)] , then

The resistance R of a conductor varies with temperature t as shown in the figure. If the variation is represented by R_(t) = R_(0)[1+ alphat +betat^(2)] , then