x=a(cos t+log tan(t)/(2))y=a sin tquad 9,quad x=a sec theta,y=b cos2t

If x=a(cos t+(log tan)(1)/(2)),y=a sin t then (dy)/(dx) is equal to

x=sin t, y= cos 2t.

If x=a(cos t + log tan (t/2)),y=a sin t , then what is (d^2y)/(dx^2) at t=(pi)/3 .

If x=a (cos t +log (tan ((t)/(2)) )) ,y =a sin t ,then (dy)/(dx) =

If x=a(cos t + log tan (t/2)) , y =a sin t then (dy)/(dx)=

If x=a (cos t +log (tan ((t)/(2)) )) ,y =a sin t ,then (dy)/(dx) =

x = sin t, y = cos 2 t .

Find (dy)/(dx) if: x=a(cos t+(1)/(2)ln tan^(2)(t)/(2)) and y=a sin t.x=sin t sqrt(cos2t) and y=cost sqrt(cos2t)

x = "sin" t, y = "cos" 2t