Let `A = [[cos alpha, -sin alpha],[sin alpha, cos alpha]]` and `A^(32) = [[0, -1],[1,0]]` (A) 0 (B) `(pi)/(32)` (C) `(pi)/(64)` (D) `(pi)/(16)`

Let A_(alpha)=[[cos alpha,-sin alpha,osin alpha,cos alpha,00,0,1]]

If A=[(cos alpha, -sin alpha, 0),(sin alpha, cos alpha,0),(0,0,1)] then A^(-1) is

Let A=([cos alpha,-sin alphasin alpha,cos alpha]),(alpha in R) such that A^(32)=([0,-11,0]). Then a value of alpha is:

Let alpha=(pi)/(5) and A,=[[cos alpha,sin alpha-sin alpha,cos alpha]] then B=A^(4)-A^(3)+A^(2)-A is

Let A = [{:(cos alpha,- sin alpha ), ( sin alpha , cos alpha ):}], (a in R) such that A ^(32) = [{:(0,-1), (1, 0):}] is the value of alpha is (pi)/(2^(k)), then the value of k is

Let A = [{:("cos"alpha, -"sin"alpha), ("sin"alpha, "cos"alpha"):}], (alpha in R) such that A^(32) = [{:(0, -1), (1, 0):}] . Then, a value of alpha is

If 0

Calculate cos ((alpha)/(2)) if sin alpha=4/5 and alpha alpha in ((-3pi)/(2),-pi)