Let `S_(1)` is set of minima and `S_(2)` is set of maxima for the curve `y=9x^(4)+12x^(3)-36x^(2)-25` then (A) `S_(1)={-2,-1},S_(2)={0}` (B) `S_(1){-2,1},S_(2)={0}` (C) `S_(1)={-2,1}:S_(2)={-1}` (D) `S_(1)={-2,2},S_(2)={0}`

If S_(1) and S_(2) are respectively the sets of local minimum and local maximum point of the function, f(x)=9x^(4)+12x^(3)-36x^(2)+25, x in R , then (a) S_(1)={-2}:S_(2)={0,1} (b) S_(1)={-2,0}:S_(2)={1} (c) S_(1)={-2,1}:S_(2)={0} (d) S_(1)={-1}:S_(2)={0,2}

If 3x^(4)-27x^(3)+36x^(2)-5=0 then s_(1)+s_(2)=

S_(2n+1)-S_(2) must be equal to (A)((S_(1)-S_(2)))/(3)(1+(1)/(2^(2n-1)))

If P is a point on the hyperbola 16x^(2) - 9y^(2) = 144 whose foci are S_(1)" and " S_(2) " then : " | S_(1) P - S_(2) P | =

If alpha,beta are the roots of x^(2)+x+1=0 , and s_(n)=alpha^(n)+beta^(n) , then |[3,1+S_(1),1+S_(2)],[1+S_(1),1+S_(2),1+S_(3)],[1+S_(2),1+S_(3),1+S_(4)]|=?

Find the area of the reigon defined by the set S = S_(3) - S_(1) - S_(2) . Where S_(1) = {(x, y), x^(2) + 2y^(2) le 2}, S_(2) = {(x, y): 2x^(2) + y^(2) le 2} and S_(3) = {(x,y): x^(2) + y^(2) le 2}

Let S be the set of all real roots of the equation 4^x (4^x -1)+2=|4^x -1|+|4^x-2) .Then S:

Consider the parabolas S_(1)=y^(2)-4ax=0 and S_(2)=y^(2)-4bx=0.S_(2) will S_(1), if

Let S_(1), S_(2) and S_(3) be three sets defined as S_(1)={z in CC:|z-1| le sqrt(2)} S_(2)={z in CC : Re((1-i)z) ge1} S_(3)={z in CC : Im(z) le 1} Then the set S_(1)cap S_(2) cap S_(3)