The perpendicular distance of point `(2,-1,4)` from the line `(x+3)/(10)=(y-2)/(-7)=(z)/(1)` lies between (A) (2,3) (B) (3,4) (C) (4,5) (D) (1,2)

The perpendicular distance of the point (1,2,3) from the line (x-1)/(2)=(y-3)/(1)=(z-4)/(1)

Perpendicular distance of the point (1, 2, 3) from the line (x-6)/3=(y-7)/2 = (z-7)/(-2) is

the distance of the point (2,3,4) from the line (1-x)=(y)/(2)=(1)/(3)(1+z)

The length of the perpendicular from the point (2, -1, 4) on the straight line, (x+3)/(10)=(y-2)/(-7)=(z)/(1) is

If the length of perpendicular from the point (-1,2,-2) on the line (x+1)/(2)=(y-2)/(-3)=(z+2)/(4) is d then d^(2)

The foot of the perpendicular from (2,4,-1) to the line (x+5)/(1)=(y+3)/(4)=(z-6)/(-9) is

(a) Find the foot of the perpendicular from the point (i) (2, -1,5) on the line : (x -11)/(10) = (y + 2)/(-5) = (z + 8)/(11) (ii) (0,2,3) on the line (x +3)/(5) = (y-1)/(2) = (z + 4)/(3) . (b) Also, find the length of perpendicular in part (ii).