In a mixture of A and B having vapour pressure of pure A and B are 400 m Hg and 600 mm Hg respectively. Mole fraction of B in liquid phase is 0.5. calculate total vapour pressure and moel fraction of A and B in vapour phase-

The vapour pressure of pure benzene and toluene are 160 and 60 mm Hg respectively. The mole fraction of benzene in vapour phase in contact with equimolar solution of benzene and toluene is :

At 300 K the vapour pressure of two pure liquids, A and B are 100 and 500 mm Hg, respectively. If in a mixture of a and B, the vapoure is 300 mm Hg, the mole fractions of a in the vapour phase, respectively, are -

The vapour pressure of pure liquids A and B is 450 and 700mm Hg , respectively, at 350K. Find out the composition of the liquid mixture if the total vapour pressure is 600mm Hg . Also find the composition of the vapour phase.

The vapour pressures of pure liquids A B are 450 mm and 700 mm of Hg respectively at 350 K. Calculate the compositon of the liquid mixture if total vapour pressure is 600 mm of Hg. Also find the composition in the Vapour phase.