The internal resistance of a cell is determined by using a potentiometer. In an experimetn, an external resistance of `60 Omega` is used across the given cell. When the key is closed, the balance length on the potentiometer decreases form 72 cm to 60 cm. calculate the internal resistance of the cell.

The internal resistance of a cell by potentiometer is given by

Using a potentiometer how do you determine the internal resistance of a cell?

How will you use potentiometer to determine internal resistances of a cell?

Give the formula to determine internal resistance of a cell using a potentiometer.

Explain the use of potentiometer for determining he internal resistance of cell.

In an experiment to find the internal resistance of a cell by a potentiometer, a balance was obtained for 50 cm length of the potentiometer wire, with a cell of e.m.f. 2V. When the cell was shunted by a resistance of 2 Omega , the balancing length of the potentiometer wire was 40 cm. What was the internal resistance of the cell ?

When a resistor of 5 Omega is connected across a cell, its terminal potential differnce is balanced by 140 cm of potentiometer wire and when a resistance of 8 Omega is connected across the cell, the terminal potential difference is balanced by 160 cm of the potentiometer wire. Find the internal resistance of the cell.

A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery used across the potentiometer wire, has an emf of 2V and negligible internal resistance. The potentiometer itself is 4m long. When the resistance 'R_(1)' , connected across the given cell has values of (i) infinity (ii) 9.5Omega , the balancing length on the potentiometer wire are found to be 3m and 2.85m respectively. The value of internal resistance of the cell is

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10 Omega is connected in parallel to the cell, the balancing length changes to 60 cm. The internal resistance of the cell is

3V poteniometer used for the determination of internal resistance of a 2.4V cell. The balanced point of the cell in open circuit is 75.8cm. When a resistor of 10.2Omega is used in the external circuit of the cell the balance point shifts to 68.3cm length of the potentiometer wire. The internal resistance of the cell is