Integral curve satisfying `y'=(x^2+y^2)/(x^2-y^2)`, has the slope at the point (1,0) of the curve equal to

Integral curve satisfying y'=(x^2 +y^2)/(x^2-y^2) and y' (1) ne 1 has the slope at the point (1, 0) of the curve equal to:

Integral curve satisfying y'=(x^2 +y^2)/(x^2-y^2) and y' (1) ne 1 has the slope at the point (1, 0) of the curve equal to:

Integral curve staisfying (dy)/(dx)=(x^2+y^2)/(x^2-y^2) , y (1) = 1 has the slope at the point (1,0) of the curve equal to :

Find the slope of the tangent to the curve y=(x-2)^2 at x=1

The gradient (slope) of a curve at any point (x,y) is (x^(2) -4)/(x^(2)) . If the curve passes through the point (2,7) , then the equation of the curve is. . . .

Find the equation of the curve passing through the point (2,-3), given that the slope of the tangent to the curve at any point (x,y) is (2x)/(y^(2))

Find the equation of a curve passing through the point (-2,3) , given that the slope of the tangent to the curve at any point (x, y) is (2 x)/y^2

Find the equation of the curve passing through the point (-2,3) given that the slope of the tangent to the curve at any point (x,y) is (2x)/(y^(2))