5x-y=-7
2x+3z=1
3y-z=5

4x -5y-11z=12,. x-3y+z=1 2x + 3y-7z = 2

Solve the following system of equations: 2x-3y+5z=11, 5x+2y-7z=-12, -4x+3y+z=5

The number of solutions of the system of equations: 2x+y-z=7,\ \ x-3y+2z=1,\ \ x+4y-3z=5 is (a) 3 (b) 2 (c) 1 (d) 0

Add: 5x - 8y + 2z, 3z - 4y - 2x, 6y - z - x and 3x - 2z - 3y

Solve, using matrices : 2x-y+3z=5 , 3x+2y-z=7 and 4x+5y-5z=9

The number of solutions of the system of equations 2x+y-z=7,x-3y+2z=1, x+3y-3z=5 is

if 2x+3y-3z=0;5x-2y+2z=19;x+7y-5z=5. Then the value of x+y-z is

The following system of equations 5x-7y+3z=3, 5x+y+3z=7 and 5x+3y+2z=5 is

The following system of equations 5x-7y+3z=3, 5x+y+3z=7 and 5x+3y+2z=5 is