" In Fig."7.238," PQ IIBC and "AP:PB=1:2" .Find "(areac(Delta A))/(arcsin AA)

In Fig.4.236,PQBC and AP:PB=1:2 Find (area(APQ))/(area(ABC)).( FIGURE )

PQabs()BC and AP:PB = 1 : 2 find ("area"(DeltaAPQ))/("area"(DeltaABC)) .

In Figure 1,PQ|BC and AP:PB=1:2* find the ratio of (ar Delta APQ)/(ar Delta ABC)

In Figure 1, PQ || BC and AP : PB = 1 : 2.find the ratio of (arDeltaAPQ)/(arDeltaABC)

The given figure shows a parallelogram ABCD with area 324sq. cm. P is a point in AB such that AP:PB= 1:2 . Find the area of DeltaAPD .

In Fig. 7 .27, if DeltaABC~ DeltaDEF and their sides are oflengths (in cm) as marked along them, then find the lengths of the sides of each triangle.

If triangle ABC~triangle PQR and AB:PQ=2:3 , then find x and y . (A(triangle ABC))/(A(triangle PQR))=x/(PQ^2)=4/y .

In adjoining figure, AP _|_ BC , AD || BC ,then find Ar.(Delta ABC) : Ar.(Delta BCD) Fig.

Given triangle ABC ~ triangle PQR if (AB)/(PQ)=1/3 then find (ar triangle ABC)/(ar triangle PQR)

Points P and Q lie on the sides AB and AC of triangle ABC respectivey such that line segment PQ is parallel to side BC. If the ratio of AP : PB is 1 : 4 and area of Delta APQ is 4 square cm., what is the area of trapezium PQCB ?